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-x^2+200x-2100=0
We add all the numbers together, and all the variables
-1x^2+200x-2100=0
a = -1; b = 200; c = -2100;
Δ = b2-4ac
Δ = 2002-4·(-1)·(-2100)
Δ = 31600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{31600}=\sqrt{400*79}=\sqrt{400}*\sqrt{79}=20\sqrt{79}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-20\sqrt{79}}{2*-1}=\frac{-200-20\sqrt{79}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+20\sqrt{79}}{2*-1}=\frac{-200+20\sqrt{79}}{-2} $
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